Bytes to int или float должно получиться

>>> struct.unpack('>H', b'\x47\xa5')
(18341,)
>>> struct.unpack('>H', b'\x4b\x13')
(19219,)

[0x3B, 0xF1, 0x30, 0x39]

Раз так, то просто:
>>> a1, a2, b1, b2 = struct.unpack('BBBB', b'\x3b\xf1\x30\x39')
>>> a = f'{a1}.{int(a2*3.9)}'
>>> b = f'{b1}.{int(b2*3.9)}'
>>> a, b
('59.939', '48.222')

examples = [
    b"\x47\xA5", b"\x4B\x13", b"\x4B\x32", b"\x0E\xFF",
    b"\x0C\xA3", b"\x0D\x60", b"\x3B\xF1", b"\x30\x39"
]
 
for example in examples:
    number, value = 0, int.from_bytes(example, 'big')
    for i, bit in enumerate(f"{value:016b}"):
        number += int(bit) * 2**(7 - i)
    print(f"PAYLOAD: {example.hex()}, NUMBER: {number:.3f}")
 
# PAYLOAD: 47a5, NUMBER: 71.645
# PAYLOAD: 4b13, NUMBER: 75.074
# PAYLOAD: 4b32, NUMBER: 75.195
# PAYLOAD: 0eff, NUMBER: 14.996
# PAYLOAD: 0ca3, NUMBER: 12.637
# PAYLOAD: 0d60, NUMBER: 13.375
# PAYLOAD: 3bf1, NUMBER: 59.941
# PAYLOAD: 3039, NUMBER: 48.223

struct.unpack('f', val) - тоже не дает нужные данные...

 
Байты = Результат
[ 0x46, 0xF2, 0x2A, 0x00, 0x00, 0x00, 0x00, 0x00 ] = 60,541
[ 0x46, 0xF1, 0x9C, 0x00, 0x00, 0x00, 0x00, 0x00 ] = 60,402
[ 0x46, 0xF1, 0x68, 0x00, 0x00, 0x00, 0x00, 0x00 ] = 60,352