Разбить дату на 3 переменные

string dt = "31/12/2012";
int d, m, y;
istringstream iss(dt);
(iss >> d).get();
(iss >> m).get();
iss >> y;

#include<iostream>
using namespace std;
struct date {
    int day;
    int month;
    int year;
    char ch;
    date() :day(0), month(0), year(0), ch('/') {}
};
void input(date&dd) {
    cin >> dd.day >> dd.month >> dd.year;
}
void output(const date&dd) {
    cout << dd.day << dd.ch << dd.month << dd.ch << dd.year << endl;
}
int main() {
    date mydate;
    input(mydate);
    output(mydate);
    system("pause");
    return 0;
}

(iss >> d).get();

cin.sync()

std::string date("12/12/2015");
std::vector<std::string> result;
boost::split(result, date, boost::is_any_of("/"));
// тут result[0] == "12", result[1] == "12", result[2] == "2015"

#include <iostream>
#include <sstream>
#include <string>
#include <locale>
#include <cstddef>
 
int main()
{
    std::ctype<char>::mask table[std::ctype<char>::table_size] = { std::ctype<char>::mask() };
    table[static_cast<std::size_t>('/')] = std::ctype<char>::space;
 
    std::string str = "12/12/2015";
    std::istringstream stream(str);
    stream.imbue(std::locale(stream.getloc(), new std::ctype<char>(table)));
 
    std::string d, m, y;
    stream >> d >> m >> y;
 
    std::cout << d << " " << m << " " << y << std::endl;
 
    return 0;
}